Question
How many solutions does the following equation have?
2x^2 - 3x + 5
(I was going to say just one, I don’t know if that’s correct or not.)
2x^2 - 3x + 5
(I was going to say just one, I don’t know if that’s correct or not.)
Asked by: USER9261
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160 Answers
Answer (160)
All quadratic equations have 2 roots; they can be 2 real, different ones, or 2 real, identical ones, or 2 imaginary ones or 2 complex ones. You can tell immediatey from the discriminant b^2-4a(c):
If the D is +, you'll have 2 real, unequal roots;
If 0, you'll have 2 real, equal roots;
If the D is -, you'll have 2 complex or imaginary roots, different
Here a=2, b= -3 and c =5, so the discrim. is (-3)^2 - 4(2)(5) = 9-40 = -36.
Because the discrim. is -, you'll have 2 complex roots.
If the D is +, you'll have 2 real, unequal roots;
If 0, you'll have 2 real, equal roots;
If the D is -, you'll have 2 complex or imaginary roots, different
Here a=2, b= -3 and c =5, so the discrim. is (-3)^2 - 4(2)(5) = 9-40 = -36.
Because the discrim. is -, you'll have 2 complex roots.