Question
The length of a rectangular piece of steel in a bridge is 3 meters less than double the width. The perimeter of the piece of steel is 24 meters. Find the length of the piece of steel. Find the width of the piece of steel.
Asked by: USER2547
223 Viewed
223 Answers
Answer (223)
length = 2×width -3
or
L = 2w - 3
perimeter = 24 meters
or
p = 24m
p = 2L + 2w
or
24 = 2(2w-3) + 2w ( Remember L = 2w +3)
24 = 4w -6 +2w
24 = 6w + 6
24 - 6 = 6w
18 = 6w
18/6 = w
3 = w
Now that we know ,w, we can find L.
p = 2L + 2w
24 = 2L +2(3)
24 = 2L + 6
24 -6 = 2L
18 = 2L
18/2 = L
9 = L
Now, we can check if the answer makes sense.
p = 2L + 2w
24 = 2(9) + 2(3) (L = 9 & w =3 )
24 = 18 + 6
24 = 24
the answer checks!
or
L = 2w - 3
perimeter = 24 meters
or
p = 24m
p = 2L + 2w
or
24 = 2(2w-3) + 2w ( Remember L = 2w +3)
24 = 4w -6 +2w
24 = 6w + 6
24 - 6 = 6w
18 = 6w
18/6 = w
3 = w
Now that we know ,w, we can find L.
p = 2L + 2w
24 = 2L +2(3)
24 = 2L + 6
24 -6 = 2L
18 = 2L
18/2 = L
9 = L
Now, we can check if the answer makes sense.
p = 2L + 2w
24 = 2(9) + 2(3) (L = 9 & w =3 )
24 = 18 + 6
24 = 24
the answer checks!