Question
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Two planes left the same airport traveling in opposite directions. The first plane left at 9:00 a.m. and 2.25 hours later, the two planes were 1825 miles apart. The second plane left at 10:00 a.m. and its average rate was 108 miles per hour slower than the first plane's average rate. Let x represent the first plane's average rate. What was the first plane's average rate? Enter an equation that can be used to solve this problem in the first box. Solve for x and enter the first plane's average rate in the second box.
WHAT IS THE EQUATION AND WHAT IS THE ANSWERRR???
Two planes left the same airport traveling in opposite directions. The first plane left at 9:00 a.m. and 2.25 hours later, the two planes were 1825 miles apart. The second plane left at 10:00 a.m. and its average rate was 108 miles per hour slower than the first plane's average rate. Let x represent the first plane's average rate. What was the first plane's average rate? Enter an equation that can be used to solve this problem in the first box. Solve for x and enter the first plane's average rate in the second box.
WHAT IS THE EQUATION AND WHAT IS THE ANSWERRR???
Asked by: USER6137
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500 Answers
Answer (500)
Answer:
The Average rate of the first plane is 560 mph
Step-by-step explanation:
x = first plane's average rate (in mph)
x−108 = second plane's average rate (in mph)
First planes total distance = 2.25x
Second planes total distance = 1.25(x−108)
2.25x + 1.25(x−108) = 1825
x = 560