développer et réduire l'express (2x -3) (4x+1)

Question

Grade: Education Subject: mathematiques

Asked by: USER1972

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Answer (47)

USER5222

Best Answer

(197)

Explications étape par étape:

(2x -3) (4x+1)

développer : 2x * 4x + 2x * 1 + (-3) * 4x + (-3) * 1

réduire : 8x² + 2x + (-12)x + (-3)

→ 8x² -10 x - 3

Answered on 27 Agustus 2025

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développer et réduire l'express (2x -3) (4x+1)

Question

Answer (47)

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