Question
Calculer l'image du réel -1/3 par la fonction f(x)=
2x²
-x-3
2x²
-x-3
Asked by: USER4426
90 Viewed
90 Answers
Answer (90)
[tex]f( \frac{-1}{3})=2\times( \frac{-1}{3})^2-( \frac{-1}{3})-3 \\\\f( \frac{-1}{3}) = 2\times \frac{1}{6}+ \frac{1}{3}-3 \\\\f( \frac{-1}{3}) = \frac{1}{3}+ \frac{1}{3}- \frac{9}{3}\\\\
f( \frac{-1}{3}) = \frac{-7}{3} [/tex]