Question
bonjour, voici trois calculs dont je ne trouve pas le resultats, il faut févelopper merci de votre aide:
f(x)=2(x-3/2)²-7/2
f(x)=4-(x-1/2)²
f(x)=x(x-1)(x+2)
f(x)=2(x-3/2)²-7/2
f(x)=4-(x-1/2)²
f(x)=x(x-1)(x+2)
Asked by: USER4647
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192 Answers
Answer (192)
f(X) = 2(X-3/2)²-7/2
= 2[X²-2X×3/2+(3/2)²] - 7/2
= 2(X²-3X+9/4)-7/2
= 2X²-2×3X+2×9/4 -7/2
= 2X²-6X+9/2-7/2
f(X) = 2X²-6X+1
f(X) = 4-(X-1/2)²
= 4-(X²-2X×1/2 + (1/2)²)
= 4-(X²-X+1/4)
= 4-X²+X-1/4
= -X²+X+(16/4-1/4)
f(X) = -X²+X+15/4
f(X) = X(X-1)(X+2)
= X(X²+2X-X-2)
= X(X²+X-2)
f(X) = X³+X²-2X
= 2[X²-2X×3/2+(3/2)²] - 7/2
= 2(X²-3X+9/4)-7/2
= 2X²-2×3X+2×9/4 -7/2
= 2X²-6X+9/2-7/2
f(X) = 2X²-6X+1
f(X) = 4-(X-1/2)²
= 4-(X²-2X×1/2 + (1/2)²)
= 4-(X²-X+1/4)
= 4-X²+X-1/4
= -X²+X+(16/4-1/4)
f(X) = -X²+X+15/4
f(X) = X(X-1)(X+2)
= X(X²+2X-X-2)
= X(X²+X-2)
f(X) = X³+X²-2X