Question
Prouver que P(AUB)=P(À) +P(B) -P(AnB)
Asked by: USER5931
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37 Answers
Answer (37)
P(A)= P(A seul) +P(A interB)
P(B)= P(Bseul)+P(A interB)
P(A union B)= P(Aseul)+P(Bseul)+P(Ainter b)
P( Aunion B)= [P(Aseul)+P(A interB)] +P(Bseul)
P( A union B)= P(A) +P(Bseul)
P(Bseul)= P(B)-P(AinterB)
P(A union B)= P(A) +P(B)-P( A interB)
P(B)= P(Bseul)+P(A interB)
P(A union B)= P(Aseul)+P(Bseul)+P(Ainter b)
P( Aunion B)= [P(Aseul)+P(A interB)] +P(Bseul)
P( A union B)= P(A) +P(Bseul)
P(Bseul)= P(B)-P(AinterB)
P(A union B)= P(A) +P(B)-P( A interB)