Pertanyaan
Sisi sisi Balok mempunyai perbandingan 6: 4: 3. Luas permukaan sisi sisnya adalah 432 meter persegi. Berapakah panjang sisi sisinya
Ditanyakan oleh: USER2354
131 Dilihat
131 Jawaban
Jawaban (131)
p : l : t = 6 : 4 : 3
Luas permukaan = 432 m²
Luas = 2 x (pl + pt + lt)
432 m² = 2 x (6x.4x + 6x.3x + 4x.3x)
432 m² = 2 x (24x² + 18x² + 12x²)
432 m² = 2 x 54x²
432 m² = 108x²
x² = 432/108
x² = 4
x = √4
x = 2 cm
Panjang = 6 x 2 cm = 12 cm
Lebar = 4 x 2 cm = 8 cm
Tinggi = 3 x 2 cm 6 cm
Luas permukaan = 432 m²
Luas = 2 x (pl + pt + lt)
432 m² = 2 x (6x.4x + 6x.3x + 4x.3x)
432 m² = 2 x (24x² + 18x² + 12x²)
432 m² = 2 x 54x²
432 m² = 108x²
x² = 432/108
x² = 4
x = √4
x = 2 cm
Panjang = 6 x 2 cm = 12 cm
Lebar = 4 x 2 cm = 8 cm
Tinggi = 3 x 2 cm 6 cm
p:l:t = 6x : 4x : 3x
Lp = 2(pl + pt + lt)
432= 2(24x^2 + 18x^2 + 12x^2)
432/2 = 54x^2
216 = 54x^2
x^2 = 216/54
x^2 = 4
x = 2
panjang = 6x2 = 12
lebar = 4x2 = 8
tinggi = 3x2 = 6
Jlh pnjang rusuk/sisi
4(p+l+t)
4(12+8+6)
4(26) = 104
Lp = 2(pl + pt + lt)
432= 2(24x^2 + 18x^2 + 12x^2)
432/2 = 54x^2
216 = 54x^2
x^2 = 216/54
x^2 = 4
x = 2
panjang = 6x2 = 12
lebar = 4x2 = 8
tinggi = 3x2 = 6
Jlh pnjang rusuk/sisi
4(p+l+t)
4(12+8+6)
4(26) = 104