nilai dari integral (batas atas π/3 batas bawah 0) 2cos²xsin2x dx

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29 Agustus 2025 matematika 5 menit baca
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Grade: Education Mata Pelajaran: matematika
nilai dari integral (batas atas π/3 batas bawah 0) 2cos²xsin2x dx
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(114)
sin 2x = 2sin x cos x

= integral '0'π/3' -4 cos^3 x sin x dx
= [ - cos^4 x ]'0'π/3'
= -15/16
Dijawab pada tanggal 29 Agustus 2025

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