Întrebare
raportul atomic Fe:S:O= rap. de masa Fe:S:O masa moleculara c Fe=.......% ? va rog repede :)
Întrebare a fost pusă de: USER7824
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Răspuns (106)
FeSO4
raport atomic : 1:1:4
raport de masa:56:32:64=14:8:16
MFeSO4=AFe+AS+4AO=56+32+4×16=152g
152gFeSO4.....56gFe....32gS....64gO
100gFeSO4..........xgFe.........yeS....zgO
x=100×56/152=36,84%Fe
y=100×32/152=21,05%S
z=100×64/152=42,10%O
raport atomic : 1:1:4
raport de masa:56:32:64=14:8:16
MFeSO4=AFe+AS+4AO=56+32+4×16=152g
152gFeSO4.....56gFe....32gS....64gO
100gFeSO4..........xgFe.........yeS....zgO
x=100×56/152=36,84%Fe
y=100×32/152=21,05%S
z=100×64/152=42,10%O