Întrebare
Determinati c.m.m.d.c. al fiecarei perechi de numere si aflati de cate ori se cuprinde in fiecare numar a)15 si 24 b)35 si 55 c)24 si 32 d)450 si 900 e)21 si 26 Va rog explicati-mi cum trebuie sa aflu de cate ori se cuprinde in fiecare numar . Dau 50 de puncte
Întrebare a fost pusă de: USER9596
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302 Răspunsuri
Răspuns (302)
a)15=3x5
24=2³x3
c.m.m.d.c.=3
15:3=5 de atatea ori se cuprinde 3 in 15
24:3=8 la fel
b)35=5x7
55=5x11
c.m.m.d.c.=5
35:5=7
55:5=11
c)24=2³x3
32=2⁵
c.m.m.d.c.=2³=8
24:8=3
32:8=4
d)450=2x3²x5²
900=2²x3²x5²
c.m.m.d.c.=2x3²x5²=450
450:450=1
900:450=2
e)21=3x7
26=2x13
c.m.m.d.c.=1
24=2³x3
c.m.m.d.c.=3
15:3=5 de atatea ori se cuprinde 3 in 15
24:3=8 la fel
b)35=5x7
55=5x11
c.m.m.d.c.=5
35:5=7
55:5=11
c)24=2³x3
32=2⁵
c.m.m.d.c.=2³=8
24:8=3
32:8=4
d)450=2x3²x5²
900=2²x3²x5²
c.m.m.d.c.=2x3²x5²=450
450:450=1
900:450=2
e)21=3x7
26=2x13
c.m.m.d.c.=1
a)15 si 24
15 = 3×5
24 = 2³×3
cmmdc al numerelor ( 15 , 24) = 3
15 : 3 = 5
24 : 3 = 8
b) 35 si 55
35 = 5 x 7
55 = 5 x 11
cmmdc al numerelor ( 35, 55) = 5
35 : 5 = 7
55 : 5 = 11
c) 24 si 32
24 = 2³×3
32 = 2⁵
cmmdc al numerelor ( 24, 32) = 2³=8
24 : 8 = 3
32 : 8 = 4
d) 450 si 900
450 = 2×3²×5²
900 = 2²×3²×5²
cmmdc al numerelor ( 450, 900) = 2×3²×5²= 450
450 : 450 = 1
900 : 450 = 2
e) 21 si 26
21 = 3×7
26 = 2×13
cmmdc ( 21, 26) = 1
15 = 3×5
24 = 2³×3
cmmdc al numerelor ( 15 , 24) = 3
15 : 3 = 5
24 : 3 = 8
b) 35 si 55
35 = 5 x 7
55 = 5 x 11
cmmdc al numerelor ( 35, 55) = 5
35 : 5 = 7
55 : 5 = 11
c) 24 si 32
24 = 2³×3
32 = 2⁵
cmmdc al numerelor ( 24, 32) = 2³=8
24 : 8 = 3
32 : 8 = 4
d) 450 si 900
450 = 2×3²×5²
900 = 2²×3²×5²
cmmdc al numerelor ( 450, 900) = 2×3²×5²= 450
450 : 450 = 1
900 : 450 = 2
e) 21 si 26
21 = 3×7
26 = 2×13
cmmdc ( 21, 26) = 1